Question

If tan A = 1 and tan B=root3 then find the value of cos A cos B -sin A-sin B.
friends please answer fast​

Answer 1

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${  tan~A=1=tan~45°   }$

${tan~B=\sqrt{ 3 } =tan~60° }$

Then...

${cosA.cosB-sinA.sinB     }$

$\implies { cos45°.cos60°- sin45°.sin60°    }$

$\implies {( \frac{1}{\sqrt 2}×\frac{1}{2} )-(  \frac{1}{\sqrt 2}×\frac{\sqrt 3}{2} }$

$\implies {(  \frac{1}{2\sqrt 2}  )-(\frac{\sqrt3}{2\sqrt 2})  }$

$\implies\boxed {\blue {\frac{1-\sqrt3}{2\sqrt 2}  } }$

$\boxed{\underbrace{\mathbb {\underline{\fcolorbox {black}{pink}{AAYYUUSS123}}}}}$

Answer 2

Answer:

sorry I cant give answer coz I am in 8th class and this is not my equal question sorry army