Question

if tan A + 1 by tan A = 5 find the value of tan square A + 1 by tan square​

Answer 1

Step-by-step explanation:

$( \ \tan(a) + 1 \div \tan(a) ) = 5$

Square both sides,

On squaring we have,

${( \tan(a) + 1 \div \tan(a)) }^{2} = 25 \\ = > { (\tan(a)) }^{2} + 1 \div { (\tan(a))}^{2} </p><p> + 2( \tan(a) ) \times (1 \div \tan(a) ) = 25 \\ = > { (\tan(a)) }^{2} + </p><p>1 \div { (\tan(a))}^{2} + 2 = 25 \\ = > { (\tan(a)) }^{2} + 1 \div { (\tan(a))}^{2} = 25 - 2</p><p> = 23 \\ = > { (\tan(a)) }^{2} + 1 \div { (\tan(a))}^{2} = 23$

Ans. 23

Here you go buddy. Best of luck