If tan A=1 find sin2A + cos2A
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Answered by
1
If tan A=1
Then sin A=1/(2)^(1/2)
CosA=1/(2)^(1/2)
Sin2A=2sinAcosA=1/2
Cos2A=cos^2(A)-sin^2(A)=0
Therefore sin2A+cos2A=1/2
Answered by
1
Answer:
Given,
tanA=1
sin2A+cos2A=?
we know,
sin2A=2tanA/1+tan^(2)A
cos2A=1-tan^(2)a/1+tan^(2)A
solution,
=sin2A+cos2A
=2tanA/1+tan^(2)A + 1-tan^(2)a/1+tan^(2)A
=2.1/1+1^(2)+1-1^(2)+1+1^(2)
=2/2+0/2
=1+0
=1
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