Question

if tan a=1,tan b=2,tan y=3 then a+b+y=​

Answer 1

tan a=1

a= tan^-1 (1) = 45°

tan b=2

b= tan^-1 (2)

tan y=3

y = tan^-1 (3)

a+b+y= tan^-1 (1) + tan^-1 (2) + tan^-1 (3)

= tan^-1 (1+2+3)

= tan^-1 (6)