Question

if tan A =1 , then find the value of 2sinAcosA​

Answer 1

Answer:

tan A = 1

=> tanA = tan4 5°

=> A = 45°

SO,

2SinAcosA

= 2 * sin45 * cos45

= 2*1/√2 *1/√2

= 2*½

= 1 .

Answer 2

Answer:

tanA = 1

=> tanA = tan45°

=> A = 45°

now,

2sinA cosA

= 2 * sin45° * cos45°

= 2 * (1/√2) * 1/√2

= 2*½

= 1 .

hence the answer is 1.