Question

if tan A=1 then find value of sinA+ cos A/secA+cosecA

Answer 1

Answer:

Step-by-step explanation:

I think this is answer it will help you.

Answer 2

Answer:

$\bold{1}$

Step-by-step explanation:

$tan\ A = 1 \\ \\ \therefore\ A = 45 \\ \\ \\ sin\ A = sin\ 45 = \frac{1}{\sqrt{2}} \\ \\ cos\ A = cos\ 45 = \frac{1}{\sqrt{2}} \\ \\ sec\ A = sec\ 45 = \sqrt{2} \\ \\ cosec\ A = cosec\ 45 = \sqrt{2} \\ \\ \\ (sin\ A + cos\ A) \div (sec\ A + cosec\ A) \\ \\ = (\frac{1}{\sqrt{2}} + \frac{1}{\sqrt{2}}) \div (\sqrt{2} + \sqrt{2}) \\ \\ = \frac{2}{\sqrt{2}} \div \sqrt{2} \\ \\ = \frac{2}{\sqrt{2}} \times \frac{1}{\sqrt{2}} \\ \\ = \frac{2}{2} = \bold{1}$