Question

If tan A =1/V3 then sec2A= a.5/3 b.3/4 c.3/5 d. 4/3​

Answer 1

Answer:- Option d.

Sec^2 A = 4/3

Step-by-step explanation:

tan A = 1 / √3 = O / A

By Pythagoras theorem,

= AB^2 + BC^2 = AC^2       [∴ AB = √3, BC = 1 and AC = ?]

= [√3]^2 + 1^2 = AC^2

= 3 + 1 = 4 = AC^2

= AC = 2

= Sec A = H / A = 2 / √3

= Sec^2 A = [2 / √3]^2

                 = 4 / 3