if tan a = 12/13 evaluate 2sinacosa/cos^2a-sin^2a
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2sinacosa=sin2a
cos^2a-sin^2a=cos2a
therefore
2sinacosa/cos^2a-sin^2a=sin2a/cos2a=tan2a
now,
tan2a=2tana/1-tan^2a
=2*12/13/1-(12/13)^2
=2*(13/12)/169-144
=(13/6)/24
=13/144
cos^2a-sin^2a=cos2a
therefore
2sinacosa/cos^2a-sin^2a=sin2a/cos2a=tan2a
now,
tan2a=2tana/1-tan^2a
=2*12/13/1-(12/13)^2
=2*(13/12)/169-144
=(13/6)/24
=13/144
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