Question

If tan A=15/8, find the value of sinA

Answer 1

Answer:

Let right angle at B

Tan A = oppo/adj.

= 15/8 (given)

By pythagores therom

AC^2 = AB^2 + BC^2

AC^2 = (15)^2 + (8)^2

Ac ^2 = 225 +64

AC^2 = 289

Ac =17

Hypotenuse is 17

So, sinA = oppo. /hypo

SinA = 15/17

Answer 2

$\boxed{\mathsf{\green{Answer}} }$

$\mathsf{sinA = \dfrac{15}{17}}$

$\boxed{\mathsf{\green{Explanation}} }$

Given:

$\mathsf{tanA = \dfrac{15}{8}}$

To Find:

sinA

Solution:

w.k.t,

$\blue{\boxed{\bold{\pink{tanA = \dfrac{Opposite \: side}{Adjacent \:side}}} }}$

From Pythagoras theorem

(Hypoteneuse)² = (Adj.side)² + (opp.side)²

$\mathsf{Hyopteneuse = \sqrt{{15}^{2}+{8}^{2}}}$

$\mathsf{Hyopteneuse = \sqrt{225+64}}$

$\mathsf{Hyopteneuse = \sqrt{289}}$

$\mathsf{Hyopteneuse =17 }$

$\blue{\boxed{\bold{\red{sinA = \dfrac{Opposite \: side}{ Hypoteneuse}}} }}$

$\mathsf{sinA = \dfrac{15}{17}}$

$\texttt{\blue{Aravind}\:\red{Reddy}....!}$