Question

if tan A=15/8 then find the value of
sin A -COSA​

Answer 1

Step-by-step explanation:

tan a=sin a/cos a

$\frac{ \sin( \alpha ) }{ \cos( \alpha ) } = \frac{15}{8} \\ \sin( \alpha ) = \frac{15 \cos( \alpha ) }{8} \\ \cos( \alpha ) = \cos( \alpha ) \\ \sin( \alpha ) - \cos( \alpha ) = \\ \frac{15 \cos( \alpha ) }{8} - \cos( \alpha ) = \frac{7 \cos( \alpha ) }{8} \\ \tan( \alpha ) = \frac{opp}{adj} \\ \cos( \alpha ) = \frac{8}{17} \\ \sin( \alpha ) - \cos( \alpha ) = \frac{7 \cos( \alpha ) }{8} = \frac{7 \times 8}{17 \times 8} \\ = \frac{7}{17}$

Answer 2

Step-by-step explanation:

tan A = 15/8 = P/B

Now,

P = 15

B = 8

H = ?

H^2 = ( P )^2 + ( B )^2

= ( 15 )^2 + ( 8 )^2

= 225 + 64

= 289

H = 17

sin A = P/H

= 15/17

cos A = B/H

= 8/17

sin A - Cos A

15/17 - 8/17

7/17 :- ANSWER