If Tan A=18/17,Tan B=1/35then Tan (A-B)
Answers
Answered by
3
tan A = 18/17 & tan B = 1/35
tan A - tan B = [18/17 - 1/35] = [18 x35 - 17]/(17 x 35) = 630/595
and (1 + tan A.tan B) = 1 + 18/(17 x 35) = [17 x 35 + 18]/(17 x 35)
= 630/595
Now, tan (A - B) = (tan A - tan B)/(1 + tan A.tan B)
= [630/595]/[(630)/(595)]
= [630/595] * [(595)/(630)]
= 1
vineethavineetha:
I too know that
Apply it
Or wait a minute
I applied answer is not coming in book answer is one
We should substitute and we should cancel the values??
Oh sry
I entered a slight misspelling of it
Answered by
4
Formula:
tan(A − B) = (tan A − tan B) / (1 + tan A tan B)
Tan A=18/17,Tan B=1/35
∴tan(A − B) = (18/17 − 1/35) / (1 + 18/17×1/35)
= (18×35 − 17) / (17×35 + 18)
= 613 / 613
= 1
Therefore, tan(A − B) = 1
I hope this helps you ^_^
tan(A − B) = (tan A − tan B) / (1 + tan A tan B)
Tan A=18/17,Tan B=1/35
∴tan(A − B) = (18/17 − 1/35) / (1 + 18/17×1/35)
= (18×35 − 17) / (17×35 + 18)
= 613 / 613
= 1
Therefore, tan(A − B) = 1
I hope this helps you ^_^
Similar questions