If tan A = √2-1. Find sin Ax Cos A
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Answer:
Hey mate ! Your answer is √2/4 .
Explanation:
Tan A = √2 - 1
Tan A = opposite / adjacent (i.e) tan a = o / a
(√ 2 - 1 ) / 1 = o / a ( o = √2 - 1 , a = 1 )
By pythagoras theorem ,
o² + a² = h² (where h is the hypotenuse)
(√2 - 1 )² + (1)² = h²
2 + 1 - 2√2 + 1 = h ²
h² = [4 - 2√2 ]
Sin A = o / h , Cos A = a / h
Sin A × Cos A = ( o × a ) / h²
= (√ 2 - 1 ) / ( 4 - 2 √2)
Rationalizing the Denominator,
⇒ [( √ 2 - 1 ) × ( 4 + 2 √2 )] / [( 4 - 2 √2 )(4 + 2 √2)]
⇒ (4 √2 + 4 - 4 - 2√2 ) / ( 16 - 8 )
⇒ (2 √2) / 8
⇒ √2 / 4
Thank me if u got it
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