Question

If tan A = 2/3 and tan B =1/2, the value of tan(A + B) is

Answer 1

Answer:

$\implies \sf tan(A+B) = \dfrac{7}{4}$

Step-by-step explanation:

Formula:

$\bold{\boxed{\bold{tan(A+B)= \dfrac{tanA + tanB}{1-tanA.tanB}}}}$

now, simply plug the values in, and your work is done!

see how easy it goes like:

$\implies \sf tan(A+B) = \dfrac{\dfrac{2}{3}+\dfrac{1}{2}}{1-\dfrac{2}{3} \times \dfrac{1}{2}}$

$\implies \sf tan(A+B)= \dfrac{\dfrac{4+3}{6}}{1- \dfrac{2}{6}}$

$\implies \sf tan(A+B)= {\dfrac{\dfrac{7}{6}}{\dfrac{4}{6}}}\\\\\\\implies \bf tan(A+B)= \dfrac{7}{4}$

Answer 2

Answer:

$\small\text{According to the given question we should need to calculate the value of}$

• $tan(A + B)$

$\large \dag$Here one formula we know that is :-

• $tan(A + B) = \frac{tanA + tanB}{1 - tan \: A \: .tan \: B}$

$\small\text{According to this formula lets apply all the values we get,}$

• $tan \: (A + B) =( \frac{ \frac{2}{3} \ + \frac{1 }{2} }{1 - \frac{2}{3} . \frac{1}{2} } )$

• $tan(A + B) = ((\frac{ \frac{7}{6} }{ \frac{4}{6} } ))$

• $tan(a + b) = ((\frac{7}{4}))$

• $\small\text{Hence,this is the perfect answer to your question.}$