Question

if tan a=2 ...................cosec a

Answer 1

the answer is. (12-root5)/2

Answer 2

Your answer is ---

Given, tanA = 2.

we have

secA sinA + tan^2A - cosecA

= 1/cosA sinA + tan^2A - 1/sinA
[ °•° secA = 1/cosA ]

= sinA/cosA + tan^2A - 1/tanA/√1+tan^2A

[ °•° sinA = tanA/√1+tan^2A ]

= tanA + tan^2A - 1/tanA/√1+tan^2A

= 2 + 2^2 - 1/2/√1+2^2 [ given tanA = 2 ]

= 2 + 4 - 1/2/√5

= 6 - √5/2

= (12 - √5)/2



【 Hope it help you 】