If tan (A+20) = Cot(3A - 30) where A is an acute angle then the value of A =
[25°, 30°, 45°, 10°]
please solve and show me
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Answer:
A= 25 degrees
Step-by-step explanation: Using compound angles, we know that cotA = tan(90-a)
Cot(3a-30) = tan(90-(a+20))
cot(3a-30) = cot (a+20)
cancelling cot on both sides,
3a-30 = a+ 20
2a= 50
a= 25
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