Question

if tan A=2020/2021,tanB=1/4041 then tan(A+B)=_______​

Answer 1

Answer:

$tan(A−B)=1+tanA.tanBtanA−tanB</p><p></p><p></p><p>⇒  tan(A−B)=1+34×7134−71</p><p></p><p></p><p>⇒  tan(A−B)=1+2142128−3</p><p></p><p></p><p>⇒  tan(A−B)=21252125</p><p></p><p></p><p>⇒  tan(A−B)=1</p><p></p><p></p><p>⇒  A−B=tan−1(1)</p><p></p><p></p><p>⇒  A−B=4π</p><p></p><p></p><p>$

Step-by-step explanation:

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