If tan A=3/4 and A+B=90, find cot B
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A+B =90°
⇒A= 90°-B
tanA = 3/4
⇒tan(90°-B) = 3/4
∵tan(90°-A) = cotA
∴tan(90°-B) = 3/4
⇒cotB = 3/4
⇒A= 90°-B
tanA = 3/4
⇒tan(90°-B) = 3/4
∵tan(90°-A) = cotA
∴tan(90°-B) = 3/4
⇒cotB = 3/4
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