If tan A=3/4,Find cos A and cose
c A
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Answered by
4
Answer:
tan A=3/4
tan A= opposite/adjacent
AB=3
BC=4
using Pythagoras theorem
AC=√(AB²+BC²)
AC=√3²+4²=√9+16=√25
AC=5
cosA =adjacent/hypotenuse
cos A =4/5
cosecA=1/sinA
sinA =opposite/hypotenuse
sin A=3/5
cosec A=5/3
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Answered by
1
Answer:
cos A=4/5
cosec A=5/4
Step-by-step explanation:
tan=opp/adj
ac^2=ab^2+bc^2
ac=√16+9
ac=5
cos A=adj/hyp
4/5
cosecA=hyp/opp
5/4
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