if tan A= 3/4, find cosA and cosec
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Answer:
Sec A=(25/16)^0.5= +/-5/4. Cot A=1/tan A=1/(3/4)=4/3. cosec^2 A= 1+cot^2 A=1+(4/3)^2=1+16/9=25/9
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tan A =3/4 =perpendicular / base
perpendicular is 3 units .
base is 4 units.
we know formula of hypotenuse.
H² = P²+ B²
H² = 3² +4²
H = 5 units
cos A = base /hypotenuse
cosA = 4/5
cosec A = hypotenuse/perpendicular
cosec A = 5/3....
may this helps
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