Question

if tan A=3/4 find tanA /1+Tan^2A

Answer 1

Answer:

12/25

Step-by-step explanation:

$\frac{ \tan( \alpha ) }{1 + { \tan( \alpha ) }^{2} } \\ \frac{ \frac{3}{4} }{1 +( \frac{3}{4} ) {}^{2} } \\ \frac{ \frac{3}{4} }{1 + ( \frac{9}{16}) } \\ \frac{ \frac{3}{4} }{ \frac{16 + 9}{16} } \\ \frac{3}{4} \times \frac{16}{25} \\ \frac{12}{25} \: \: \: \: \: \: ans$

Answer 2

Answer:

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