If tan A = 3/4 find the value of 1/sin A + 1/ cos A
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tan A =3/4=PERPENDICULAR/BASE
AB=4;BC=3
then in triangle by Pythagoras theorem
(AC)^2=(AB)^2+(BC)^2
(AC)^2=(4)^2+(3)^2
(AC)^2=16+9
(AC)^2=25
AC=5=HYPOTENUSE
sin A=Perpendicular/hypotenuse
sin A=3/5
cos A=Base/hypotenuse
cos A=4/5
1/sin A=1 / 3/5
1/cos A=1 / 4/5
1/sin A+1/cos A
=1 / 3/5+1 / 4/5
=5/3+5/4
=20+15/12
=35/12
HOPE THIS HELPS YOU
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