Question

If Tan A =3/4 find the value of secA and CosA

Answer 1

tan A=3/4.

Sec^2 A= 1+tan^2 A= 1+(3/4)^2=1+9/16=25/16.

Sec A=(25/16)^0.5= +/-5/4.

Cot A=1/tan A=1/(3/4)=4/3.

cosec^2 A= 1+cot^2 A=1+(4/3)^2=1+16/9=25/9.

Cosec


A=(25/9)^0.5=+/-5/3.

Cos 16l25

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Answer 2

IN THIS ABOVE QUESTION

TAN A= 3/4

OR, SINA/COSA =3/4

SUPPOSE, SIN A= 3X. AND COS A= 4X.

SECA= 1/ COSA = 1/4X =4X=4.

COSA = 1 / SECA = 1/4.

HOPE IT HELPS YOU.