Question

If tan A = 3/4 then find the value of sin A.​

Answer 1

Step-by-step explanation:

tanA=opp/adj

=3/4

So the hypotenuse=√(3x^2+4x^2)

=√(9+16)

=√25

=5x

sinA=opp/hyp

=3x/5x

=3/5

Answer 2

Answer:

If tan A = 3/4 then the value of sin A.=3/5 or -3/5

Step by step. Explanation:

Given tan(A) = 3/4

=> sin(A)/cos(A) = 3/4

=> sin(A)/{√(1-sin^2(A)} = 3/4

=> 4sin(A) = 3√(1-sin^2(A))

=> 16sin^2(A) = 9(1-sin^2(A))

=> 16sin^2(A) = 9 - 9sin^2(A)

=> 25sin^2(A) = 9

=> sin^2(A) =9/25

=> sin(A) = 3/5 or -3/5

=> sin(A) = 3/5 or -3/5 [ as -3/5 <1]

OR

TanA=opposite side of A/adjacent side of A

Given TanA=3/4

opposite side of A =, 3

adjacent side of A = 4

Therefore hypotenuse^2 = 3^2 + 4^2

hypotenuse^2 = 9+16

hypotenuse = 5

Then SinA= opposite side of A/hypotenuse

SinA= 3/5.