Question

If tan A =3/4,
then prove that sin A
cos A =
12/25
​

Answer 1

Step-by-step explanation:

As sec2A−tan2A=1⇒secA=±tan2A+1

=±169+1=±1625=±45

⇒cosA=secA1=±54 

And sin2A+cos2A=1

⇒sinA=±1−cos2A=±1−2516

=±259=±53

⇒sinAcosA=2512

I HOPE IT'S HELP

Answer 2

Answer:

tanA=3/4

perpendicular=3

base=4

then hypotenuse=?

now,

h=√9+16

=√25

=5

from questions,

sinA.cosA=12/25

=> p/h.b/h=12/25

=>3/5.4/5=12/25

=>12/25=12/25

.•.RHS=LHS proved