Question

if tan A=3/4 then sec square A-tan square A

Answer 1

Answer:

tan(theta)=3/4 sec^2(theta)=1+tan^2(theta)=1+ (3/4)^2=1+9/16=(16+9)/16=25/16 sec(theta)= square root of(25/16)=5/4 ...

Answer 2

Answer:

Given:

tanA=3/4

To find:

Sec²A-tan²A

Solution:

Method-1

As we know that,

From the identity,

Sec²A-tan²A=1

Method-II

tanA=3/4

secA=5/4

tan²A-sec²A=25/16-9/16

=16/16=1

Step-by-step explanation:

Hope it helps you..........