Question

if tan A=3%4 then sin A + cos A.................


​

Answer 1

Answer:

dewier new nohow

Step-by-step explanation:

Answer 2

Answer:

Step-by-step explanation:

tanA = 3/4 ⇒ p/b = 3/4 ⇒ p = 3k & b = 4k

Therefore, h=√(3k)² + (4k)² = 5k

Hence, sinA cosA = p/h×b/h = pb/h² = (3k×4k)/25k² = 12k²/25k² = 12/25