Question

If tan A=3/4and angle c = 90 then find--- sec squareA+2tan squareA​

Answer 1

Step-by-step explanation:

Given

$\tan(a) = \frac{p}{b} = \frac{3}{4}$

By pytagoras theorem

${h}^{2} = { p}^{2} + {b}^{2}$

${h}^{2} = {3}^{2} + {4}^{2}$

${h}^{2} = 9 + 16$

$h = \sqrt{25}$

$h = 5$

Now,

$\frac{ {5}^{2} }{ {4}^{2} } + 2 \times \frac{ {3}^{2} }{ {4}^{2} }$

$\frac{25}{16} + 2 \times \frac{9}{16}$

$\frac{25}{16} \times \frac{9}{8}$

$\frac{225}{128}$