Question

If Tan a=√3 & tan ß=1/√3 ,0<a, ß <90°
find the value
of cot (a+ß)​

Answer 1

Answer:

Given tanα= ✓3= α=60 °

tanβ= 1/✓3 = β=30 °

cot(α+β)=cot(60° +30 °)=cot90° =0