If tan a = 3 and tan B √ 1/3
0 <a B < 90° find the value of cot (a + b)
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Answer:
cot(1/20)
Step-by-step explanation:
Tan b = 1/√3
tan b= 30°
therefore, cot b = 1/ tan b
cot b= 1/30°.... eqn 1
Tan a=√3
tan a = 60°
therefore,
cot a=1/60°......eqn 2
now cot a + cot b
= cot(a+b)
= cot(1/60+1/30)
=cot(3/60)
= cot(1/20)
(OR)
tan = 20°
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