if tan a = 3 by 4 show that Sin A cos A equals to 12 by 25
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Answered by
2
tan a=b/p=3/4
h^2=3^2+4^2=25
;h=5
sin a=p/h and vos a=b/h
there for
4/5×3/5=12/25
proved
h^2=3^2+4^2=25
;h=5
sin a=p/h and vos a=b/h
there for
4/5×3/5=12/25
proved
Answered by
2
HEY USER HERE IS YOUR ANSWER :-
tan a = 3/4 = perpendicular/base
by Pythagoras theorm we will find the hypotenuse of the triangle ABC
(H)^2 = (B)^2 + (P)^2
(H)^2 = (4)^2 + (3)^2
(H)^2 = 16 + 9
(H)^2 = 25
(H) = 5
SinA = perpendicular/ hypotenuse = 3/5
CosA = Base / hypotenuse = 4/5
according to the question:-
SinA × CosA = 3/5 × 4/5
= 12/25
hence , proved ...
HOPE IT HELPS YOU !!!!
mark me as the brainliest if helps....
tan a = 3/4 = perpendicular/base
by Pythagoras theorm we will find the hypotenuse of the triangle ABC
(H)^2 = (B)^2 + (P)^2
(H)^2 = (4)^2 + (3)^2
(H)^2 = 16 + 9
(H)^2 = 25
(H) = 5
SinA = perpendicular/ hypotenuse = 3/5
CosA = Base / hypotenuse = 4/5
according to the question:-
SinA × CosA = 3/5 × 4/5
= 12/25
hence , proved ...
HOPE IT HELPS YOU !!!!
mark me as the brainliest if helps....
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