Question

if tan A =3 then what is the value of ( 5sinA-3sinA/4cosA+3cosA)​

Answer 1

Answer:

TanA=4/3

perpendicular =4 cm

base=3cm

by pythogoras theorem

hypotenuse=5cm

sinA=4/5

cosA=3/5

in question.

\begin{gathered}4( \frac{4}{5} ) - \frac{3( \frac{3}{5}) }{3( \frac{4}{5} )} + 2( \frac{3}{5} ) \\ \frac{16}{5} - \frac{ \frac{9}{5} }{ \frac{12}{5} } + \frac{6}{5} \\ \frac{22}{5} - \frac{9}{5} \times \frac{5}{12} \\ \frac{22}{5} - \frac{9}{12} = \frac{22}{5} - \frac{3}{4} \\ \frac{88 - 15}{20} = \frac{73}{20} \end{gathered}

4(

5

4

)−

3(

5

4

)

3(

5

3

)

+2(

5

3

)

5

16

−

5

12

5

9

+

5

6

5

22

−

5

9

×

12

5

5

22

−

12

9

=

5

22

−

4

3

20

88−15 = 20/73

value is 73/20