if tan A =3 then what is the value of ( 5sinA-3sinA/4cosA+3cosA)
Answers
Answered by
0
Answer:
TanA=4/3
perpendicular =4 cm
base=3cm
by pythogoras theorem
hypotenuse=5cm
sinA=4/5
cosA=3/5
in question.
\begin{gathered}4( \frac{4}{5} ) - \frac{3( \frac{3}{5}) }{3( \frac{4}{5} )} + 2( \frac{3}{5} ) \\ \frac{16}{5} - \frac{ \frac{9}{5} }{ \frac{12}{5} } + \frac{6}{5} \\ \frac{22}{5} - \frac{9}{5} \times \frac{5}{12} \\ \frac{22}{5} - \frac{9}{12} = \frac{22}{5} - \frac{3}{4} \\ \frac{88 - 15}{20} = \frac{73}{20} \end{gathered}
4(
5
4
)−
3(
5
4
)
3(
5
3
)
+2(
5
3
)
5
16
−
5
12
5
9
+
5
6
5
22
−
5
9
×
12
5
5
22
−
12
9
=
5
22
−
4
3
20
88−15 = 20/73
value is 73/20
Similar questions