Math, asked by auxelia45511, 6 months ago

If tan a =4/3 , find the value of sin a and cos a

Answers

Answered by dewanganajay1875
15

Answer:

TanA=4/3 = perpendicular /base

Perpendicular ^2+ base^2= hypotenuse ^2

4^2+3^2=Hypotenuse ^2

Hypotenuse =5

SinA= Perpendicular /Hypotenuse = 4/5

CosA=Base/Hypotenuse = 3/5

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Answered by dhairyamharidwar
2

Answer:

sin a=4/5

cos a=3/5

Step-by-step explanation:

p=perpendicular , b=base , h=Hypotenuse

 \tan(a)  =   \frac{ p}{b} =  \frac{4}{3}

h =  \sqrt{ {p}^{2}  +  {b}^{2} }

h =  \sqrt{ {3}^{2} +  {4}^{2}  }  = 5

 \sin(a)  =  \frac{p}{h}  =  \frac{4}{5}

 \cos(a)  =  \frac{b}{h}  =  \frac{3}{5}

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