Question

If tan A=4/3,Then find sinA and secA​

Answer 1

Step-by-step explanation:

let P be perpendicular

B be the base

and H be the hypotenuse

given,

tan A =4/3

P/B = 4/3

squaring both sides

P^2 / B^2 = 16/9

we know that,

P^2 + B^2 = H^2

16 + 9 = H^2

25 = H^2

thus, H=√25

H = 5 units

sin A = P/H = 4/5

sec A = H/B = 5/3