Question

If tan A =4/3 ,then (sinA+cosA)=?

Answer 1

tan A = 4/3

tan A = Perpendicular/Base

P = 4
B = 3

H^2 = P^2 + B^2
H^2 = 4^2 + 3^2
H = √25
H = 5
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Now,

sinA + cosA
= (P/H) + (B/H)
= (P+B)/H

= (4+3)/5
= 7/5

or, 1.4
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Answer 2

tanA=SinA/CosA=4/3
here P=4 and B=3
so by P.G.T. P2+B2=H2
                     9+16=H2
                       H2=25
                        H=5
so SinA= 4/5
and Cos A=3/5
according to question (sinA+cosA)
                                   =4/5+3/5
                                   =7/5