Question

if tan A=4/3 then the value of sec A ​

Answer 1

GIVEN-

Tan A=4/3

TO FIND-

Sec A

SOLUTION-

Tan A =4/3

so,Tan^2 A =16/9

we know-

1+tan^2 A= Sec^2 A

1+(16/9)=Sec^2 A

25/9=sec^2 A

5/3=sec A

so, Sec A =5/3.

please mark as BRAINLIEST.

Answer 2

$tanA= \frac{4}{3}$

$We \: know \: that,$

$tanA= \frac{Perpendicular}{Base}$

$\therefore$ By Pythagoras Theorem,

$(hypotenuse)^2=(perpendicular)^2 + (base)^2$

$\implies$ $(4)^2+(3)^2$

$\implies$ 16+9

$\implies$ 25

$\implies$ $(hypotenuse)= \sqrt{2}{5}$

$\implies$ (hypotenuse)=5

$\implies$ $secA= \frac{hypotenuse}{base}$

$\therefore$ $secA= \frac{5}{3}$

$\bold{\boxed{Hope \: it \: helps \: uh!}}$