if tan A =4 then 1/1 0(tan square A +2 sec square A)=
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Answer:
Answer is 33
Step-by-step explanation:
Given: TanA=4
Now, Tan²A = 4² = 16
Sec²A= Tan²A + 1
Therefore, Sec²A = 16 + 1 = 17
now we got the values of both Tan²A and Sec²A
So, 1/Tan²A+ Sec²A =1/ 16 + 17 = 1/33
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