Question

if tan a = 40÷ 9 find 1÷ sec A​

Answer 1

Answer:

tan a=p/b

p/b=40/9

so, 1/sec a=cos a (reciprocal)

cos a=b/h

h²=p²+b²

h=√p²+b²

h=√40²+9²

h=√1681

h=41

therefore, b/h=9/41 or 1/sec a=9/41