if Tan A=5/12 ,find the value of (Sin A+cos A) sec A
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tan A = 5/12
tan tita = sin teeta / cos teeta
So , sin A = 5
cos A = 12
Sec teeta = 1 / tan teeta
so , sec A = 12/5
(sin A + cos A) sec A
= (5+12)12/5
= 17 X 12/5
= 204/5
= 40.8
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