Question

if tan a =5/12 find the value of [SIN A +COS A]SEC A

Answer 1

Answer:

Hii friend,

Tan A = 5/12 => P/B

P = 5 , B = 12

By pythagoras theroem,

(H)² = (B)² + (P)²

(H)² = (12)² + (5)²

(H)² = 144+25

H = ✓169 = 13

Therefore,

Sin A = P/H => 5/13

And,

Cos A = B/H => 12/13

Sec A = H/B => 13/12

(SinA + CosA ) SecA

(5/13 + 12/13) 13/12

=> (5+12/13) × 13/12

=> 17/13 × 13/12

=> 17/12

Step-by-step explanation:

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