if tan A=5/12 , FIND THE VALUE OF (SIN A + COS A) SEC A
Sakshi15403:
i think answer is 17/12
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Answered by
442
Hey !!!
tanA = 5/12 = p/b
h = √12²+ 5²
h = √144+ 25
h = √169
h = 13
now , sinA = p/h = 5/13 ---------1)
cosA = b/h = 12/13 ---------2)
secA = h/b = 13/12
now, putting these value on
(sinA + cosA )secA
=>( 5/13 + 12/13 )13/12
=> 12+5/13 ×13/12
=> 17/13×13/12
=> 17/12 Answer
Hope it helps you !!!!
#Rajukumar111@@@@
tanA = 5/12 = p/b
h = √12²+ 5²
h = √144+ 25
h = √169
h = 13
now , sinA = p/h = 5/13 ---------1)
cosA = b/h = 12/13 ---------2)
secA = h/b = 13/12
now, putting these value on
(sinA + cosA )secA
=>( 5/13 + 12/13 )13/12
=> 12+5/13 ×13/12
=> 17/13×13/12
=> 17/12 Answer
Hope it helps you !!!!
#Rajukumar111@@@@
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