Question

if tan A =5÷12 find the value of sinA cosecA +CosA secA​

Answer 1

Answer:

Tan A=P/B

5/12

P=5

B=12

H=P^2+B^2

5×5+12×12

25+144

169

√169

13

sinAcosecA+cosAsecA

P/H×H/P+B/H×H/B

5/13×13/5+12/13×13/12

1+1

2