If tan A=5/6 and tan B=1/11 then show that A+B=π/4.
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Answer:
tan(A+B) = (tanA+ tanB)/(1-tanA tanB)
tan(A+B) ={ 5/6 + 1/11 } / { 1- 5/6×1/11 }
= (55+6/66 ) / (66-5/66)
= 61/61 = 1
tan(A+B) = 1
(A+B) = tan^-1(1) = pi/4
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