Question

if tan A =6/8 then find sin
A​

Answer 1

Answer:

answer is SinA = 6/10

Step-by-step explanation:

tanA=6/8

using Pythagoras theorem

(AC)² = (AB)² + (BC)²

(AC)² = (6)² + (8)²

(AC)² =36 + 64

(AC)² = 100

AC = √100 = √10×10

AC = 10

SinA = perpendicular / hypotenuse

SinA = AB/AC

SinA = 6/10

Answer 2

Answer:

3/5

Step-by-step explanation:

tanA=6/8

We know that,

secA = √(1+tan2A)

= √(1+36/64)

= √(100/64)

= 10/8

Again, cosA =1/secA=8/10

Therefore, sinA=√(1-cos2A)

= √1-64/100)

=√(36/100)

=6/10=3/5