If tan a =a/a+1 and tanb =1/2a+1 what is the value of a+b
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SOLUTION
tan (A+B)= tanA + tanB/1-tanA.tanB
=)a/(a+1)+ 1/(2a+1)/1-a/(a+1).1/(2a+1)
=)a(2a+1)+(a+1)/(a+1)(2a+1)/(a+1)(2a+1)-a/(a+1)(2a+1)
=)2a^2 + a + m+1/2m^2 +m +2m+1-m
=)2a^2 +2a+1/2a^2 +2a+1
=) tan(A+B)= 1
=) A+B= tan^-1 1
=) A+B= π/4
Hope it helps ☺️
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