Question

if

tan A+B) = 1/2
tan(A-B) = 1/3

find
tan2A=?​

Answer 1

Answer:

1/√2

Step-by-step explanation:

tan (A+B) = 3

tan(A=B) = 2

tan[(A+B) + (A-B)] = (3+2)/1 - 6= -1

tan 2A = -1

sin 2A = -1/√2

but 1 quadrant which means all angles would be positive

hence sin2A = 1/√2