Question

if tan (a-b) =1/√3, tan(a+b) = √3. find a,b 0<a+b=90°, a>b

Answer 1

A=45 and B=15 then
Tan(45-15)=tan 30=1/roor3
Tan(45+15)=tan60=root3

Answer 2

tan(a-b)=1/√3
tan(a-b)=tan30°
a-b=30..........(1)
tan(a+b)=√3
tan(a+b)=tan60
a+b=60........(2)
adding 1 and 2
we get,
2a=90
a=45°
a-b=30....(from 1)
45-30=b
b=15°


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