Math, asked by Mudit1840, 1 year ago

if tan(A+B)=1&tan(A-B)=1÷√3 than find A&B where A>B

Answers

Answered by GoKuL3112003
0

tan(a+b)=1

so a+b=45 [tan45=1]

tan(a-b)=1/√3

so

a-b=30

solving both equation we get a=37.5,b=7.5

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