Question

If tan (A + B) = 1 and tan (A-B) = 1/√3,0° <A+B < 90°, A > B, then find the values of A and B.​

Answer 1

Answer:

As we know tan 45 = 1 & tan 30 = 1/√3

Step-by-step explanation:

Answer 2

$\boxed{Question:-}$

If tan (A + B) = 1 and tan (A-B) = 1/√3,then find the values of A and B?

$\boxed{Solution:-}$

Tan(A+B)=1

[°•° Tan45°=1]

Tan(A-B)= $\frac{1}{\sqrt{3}}$ [°•° Tan30°=1/√3]

Tan(A+B)=Tan45

Tan(A-B)=Tan30

→A+B=45--(1)

→A-B=30--(2)

Add eq-(1)&(2)

Refer Attachment:-

We Get,

$\boxed{A=37.5}$

Putting A=37.5 in Eq-(1)

→37.5+B=45

→B=45-37.5

→$\boxed{B=7.5}$

$\mathcal{BE \: BRAINLY}$