If tan(a+b)=1 and tan(a-b)=1/√3, 0degree < A+B < 90, A >B. then find the value of A and B..
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tan (a+b)=1
tan (a+b)=tan45
a+b=45 1st eq.
tan(a-b)=tan 30
a-b=30 2nd eq.
add 1st and 2nd eq
2a=75
a=37.5
put the value of a in eq. 1st
a+b=45
37.5+b=45
b=45-37.5
b=7.5
tan (a+b)=1
tan (a+b)=tan45
a+b=45 1st eq.
tan(a-b)=tan 30
a-b=30 2nd eq.
add 1st and 2nd eq
2a=75
a=37.5
put the value of a in eq. 1st
a+b=45
37.5+b=45
b=45-37.5
b=7.5
jitendrasingh3577:
Can we write A and B value in decimal...
your choice
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