If tan(A+B) = 1 and tan (A-B) √1/3 find the value of A and B
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tan a+b = 1
we know tan 45=1
comparing above two
a+b= 45........... i
tan a-b = 1/√3
we know tan 30=1\√3
comparing above two
a-b = 30 .......ii
using elimination we get in i and ii
a= 37.5
b=7.5
we know tan 45=1
comparing above two
a+b= 45........... i
tan a-b = 1/√3
we know tan 30=1\√3
comparing above two
a-b = 30 .......ii
using elimination we get in i and ii
a= 37.5
b=7.5
adarsh3406:
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Answered by
1
Answer: tan 45 = 1
and. Tan 30= 1√3
So A+B= 45
A-B=30
Hence by eliminating them
A=37.5
B=7.5
Step-by-step explanation:
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